document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=170608>Question 170608</A>: <I><SPAN STYLE=\"word-break: break-all;\"> PLEASE, HELP ME WITH THIS PROBLEM! I'VE BEEN TRYING SINCE YESTERDAY AND I COULDN'T FINISH YET =( THANKS.<BR>\n" );
document.write( "In 8h, two campers rowed 15min down a river and then rowed back their campsite. The rate of the river's current was 1mph. Find the rate at which that campers row in calm water. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #125930 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=125930\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> assuming min is mi. __ t=d/r __ let x=rate in calm water\r<BR>\n" );
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document.write( "15/(r+1) + 15/(r-1) = 8 __ multiplying by (r+1)(r-1) __ 15r-15 + 15r+15 = 8r^2-8\r<BR>\n" );
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document.write( "8r^2-30r-8=0 __ dividing by 2 __ 4r^2-15r-4=0\r<BR>\n" );
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document.write( "factoring __ (4r+1)(r-4)=0\r<BR>\n" );
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document.write( "4r+1=0 __ r=-1/4 __ negative value not realistic\r<BR>\n" );
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document.write( "r-4=0 __ r=4 mph </SPAN>\n" );
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