document.write( "Question 170532: Need help!!\r
\n" ); document.write( "\n" ); document.write( "x² - 5x + 2 = 0
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Algebra.Com's Answer #125911 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
\"x%5E2+-+5x+%2B+2+=+0\"
\n" ); document.write( "Complete the square. It works like this:
\n" ); document.write( "Subtract \"2\" from both sides
\n" ); document.write( "\"x%5E2+-+5x+=+-2\"
\n" ); document.write( "Now take one-half of the co-efficient of \"x\",
\n" ); document.write( "square it and add this to both sides.
\n" ); document.write( "\"x%5E2+-+5x+%2B+%28-5%2F2%29%5E2+=+-2+%2B+%28-5%2F2%29%5E2\"
\n" ); document.write( "\"x%5E2+-+5x+%2B+25%2F4+=+-2+%2B+25%2F4\"
\n" ); document.write( "The left side is a perfect square. Rewrite it.
\n" ); document.write( "\"%28x+-+5%2F2%29%5E2+=+-%288%2F4%29+%2B+25%2F4\"
\n" ); document.write( "\"%28x+-+5%2F2%29%5E2+=+17%2F4\"
\n" ); document.write( "Now take the square root of both sides
\n" ); document.write( "\"x+-+5%2F2+=+sqrt%2817%29+%2F+2\"
\n" ); document.write( "\"x+=+%285+%2B+sqrt%2817%29%29+%2F+2\" answer 1
\n" ); document.write( "and, also, since square root is both (+) and (-)
\n" ); document.write( "\"x+=+%285+-+sqrt%2817%29%29+%2F+2\" answer 2
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