document.write( "Question 170510: Mary is 12 years old. Robin her mother is 35.\r
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document.write( "a. Write an expression for the person’s age y years from now.
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document.write( "b. Write an equation stating that Robin is twice as old as Mary. How old will they both be at this time?
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document.write( "c. What will their ages be when Robin is 3 times as old as Mary\r
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document.write( "I know that expression for the person's age y years from now is:
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document.write( "Mary: 12 + y
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document.write( "Robin: 35 + y \n" );
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Algebra.Com's Answer #125895 by Mathtut(3670)![]() ![]() ![]() You can put this solution on YOUR website! b. so when is robin twice as old as mary. Take you expressions \n" ); document.write( ": \n" ); document.write( "robin (35+y)=2 mary's 2(12+y) \n" ); document.write( ": \n" ); document.write( "35+y=24+2y--->combine like terms \n" ); document.write( ": \n" ); document.write( "y=11------->so robin will be \n" ); document.write( ": \n" ); document.write( "c. this time we have robin(35+y)=3 mary's(12+y) \n" ); document.write( ": \n" ); document.write( "35+y=3(12+y) \n" ); document.write( ": \n" ); document.write( "35+y=36+3y-->combine like terms \n" ); document.write( ": \n" ); document.write( "y=-1/2 so Robin was |