document.write( "Question 170463This question is from textbook Introductory Algebra
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\n" ); document.write( "\n" ); document.write( "12/sqrt(5x+6)=sqrt(2x+5)
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Algebra.Com's Answer #125873 by stanbon(75887)\"\" \"About 
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Solve
\n" ); document.write( "12/sqrt(5x+6)=sqrt(2x+5)
\n" ); document.write( "sqrt[5x+6)(2x+5) = 12
\n" ); document.write( "10x^2+37x+30 = 12
\n" ); document.write( "10x^2 + 37x +18 = 0
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\n" ); document.write( "x = [-37 +- sqrt(37^2 - 4*10*18)]/20\r
\n" ); document.write( "\n" ); document.write( "x = [-37 +- sqrt(649)]/20\r
\n" ); document.write( "\n" ); document.write( "x = [-37 +- 25.4755]/20\r
\n" ); document.write( "\n" ); document.write( "x = -3.1238 or x = -0.57623
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\n" ); document.write( "Only x= -0.57623 is an acceptable answer as the other makes the
\n" ); document.write( "original equation meaningless as it would involve sqrt(negative number)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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