document.write( "Question 170463This question is from textbook Introductory Algebra
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document.write( ": Solve\r
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document.write( "12/sqrt(5x+6)=sqrt(2x+5) \n" );
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Algebra.Com's Answer #125873 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Solve \n" ); document.write( "12/sqrt(5x+6)=sqrt(2x+5) \n" ); document.write( "sqrt[5x+6)(2x+5) = 12 \n" ); document.write( "10x^2+37x+30 = 12 \n" ); document.write( "10x^2 + 37x +18 = 0 \n" ); document.write( "------------ \n" ); document.write( "x = [-37 +- sqrt(37^2 - 4*10*18)]/20\r \n" ); document.write( "\n" ); document.write( "x = [-37 +- sqrt(649)]/20\r \n" ); document.write( "\n" ); document.write( "x = [-37 +- 25.4755]/20\r \n" ); document.write( "\n" ); document.write( "x = -3.1238 or x = -0.57623 \n" ); document.write( "------------- \n" ); document.write( "Only x= -0.57623 is an acceptable answer as the other makes the \n" ); document.write( "original equation meaningless as it would involve sqrt(negative number) \n" ); document.write( "================================= \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "=================================== \n" ); document.write( " \n" ); document.write( " |