document.write( "Question 170479: Jack usually mows his lawn in 7 hours. Marilyn can mow the same yard in 4 hours. How much time would it take for them to mow the lawn together?
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Algebra.Com's Answer #125864 by Mathtut(3670)\"\" \"About 
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so Jack can do 1/7 of the job per hour and Marlyn can do 1/4 of the job per hour
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\n" ); document.write( "1/7(t)+1/4(t)=1(job)----->find common denominator---->28 --.so multiply by 28
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\n" ); document.write( "4t+7t=28
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\n" ); document.write( "11t=28
\n" ); document.write( "\"highlight%28t=28%2F11%29\"or 2 6/11 hours for both to mow the lawn
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