document.write( "Question 23848: plaease help me use the substitution method to solve the linear system. \r
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document.write( " y = x-4
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document.write( " 4x+y = 26 \n" );
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Algebra.Com's Answer #12583 by ilana(307)![]() ![]() ![]() You can put this solution on YOUR website! By \"substitution,\" we mean starting with 2 equations and 2 variables, and replacing one variable to end up with 1 equation and 1 variable, which we then solve. \n" ); document.write( "Here, we have an equation of the form y=(something in terms of x), so it is simplest to substitute that equation for y in the other equation. \n" ); document.write( "So, we take x-4 for y and use that in the equation 4x+y=26, giving us 4x+(x-4)=26. \n" ); document.write( "We then simplify this to get 4x+x-4=26, so 5x-4=26, so 5x=30, and finally x=6. \n" ); document.write( "We then need only the value of y, so we use x=6 and y=x-4 to get y=(6)-4=2. \n" ); document.write( "So x=6 and y=2.\r \n" ); document.write( "\n" ); document.write( "We can check these values in both equations and they should make the statements true: \n" ); document.write( "y=x-4: 2=6-4=2, so this is true. \n" ); document.write( "4x+y=26: 4(6)+(2) = 26 \n" ); document.write( " 24+2=26 = 26, so this is true as well. \n" ); document.write( " |