document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=170404>Question 170404</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A bacteria culture starts with 120 bacteria and after three hours the population consists of 200 bacteria. assuming that the culture grows exponentially, find the poplation after 5 hours. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #125803 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=125803\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A bacteria culture starts with 120 bacteria and after three hours the population consists of 200 bacteria. assuming that the culture grows exponentially, find the poplation after 5 hours.<BR>\n" );
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document.write( "A(t) = ab^t<BR>\n" );
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document.write( "200 = 120b^3<BR>\n" );
document.write( "b^3 = 200/120 = 5/3<BR>\n" );
document.write( "b = 1.047197551....<BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "A(5) = 120(1.047197551)^5<BR>\n" );
document.write( "A(5) = 151.12<BR>\n" );
document.write( "Rounding down, A(5) = 151<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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