document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=170398>Question 170398</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A local elementary school is taking orders for a craf they will make.  After calculating the cost of supplies the profit associated with making the craft is represented by P(x)=-x^2+130x-3000, where x represents the number of crafts sold and P represents the profilt.  Determine the number of orders that could be acepted in order to make a profit. (Give the entire interval of solutions where a profit would be made) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #125791 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=125791\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the profit associated with making the craft is represented by P(x)=-x^2+130x-3000, where x represents the number of crafts sold and P represents the profilt. Determine the number of orders that could be acepted in order to make a profit.<BR>\n" );
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document.write( "Determine when P is > 0<BR>\n" );
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document.write( "Solve -x^2+130x -3000 = 0<BR>\n" );
document.write( "-(x^2-130x+3000) = 0<BR>\n" );
document.write( "(x-30)(x-100) = 0<BR>\n" );
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document.write( "Profit interval: 30 < x < 100<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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