document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=170395>Question 170395</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me solve this equation: 2x= 5x+9. The 5x+9 is in a square root. \r<BR>\n" );
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document.write( "Thank you </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #125784 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=125784\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2x=sqrt(5x+9)<BR>\n" );
document.write( "squaring both sides we get:<BR>\n" );
document.write( "4x^2=5x+9<BR>\n" );
document.write( "4x^2-5x-9=0<BR>\n" );
document.write( "(4x-9)(x+1)=0<BR>\n" );
document.write( "4x-9=0<BR>\n" );
document.write( "4x=9<BR>\n" );
document.write( "x=9/4=2.25 ans.<BR>\n" );
document.write( "x+1=0<BR>\n" );
document.write( "x=-1 ans.<BR>\n" );
document.write( "Proofs:<BR>\n" );
document.write( "2*2.25=sqrt(5*2.25+9)<BR>\n" );
document.write( "4.50=sqrt(11.25+9)<BR>\n" );
document.write( "4.5=sqrt(20.25)<BR>\n" );
document.write( "4.5=4.5<BR>\n" );
document.write( "2*-1=sqrt(5*-1+9)<BR>\n" );
document.write( "-2=sqrt(-5+9)<BR>\n" );
document.write( "-2=sqrt(4)<BR>\n" );
document.write( "-2=+-2<BR>\n" );
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