document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=170380>Question 170380</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The Sum of three numbers is 123. The Second Number is 9 Less than two times the first number. The third number is 6 more than three times the first number. Find the three numbers </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #125765 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=125765\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x+y+z=123<BR>\n" );
document.write( "y=2x-9<BR>\n" );
document.write( "z=3x+6<BR>\n" );
document.write( "x+(2x-9)+(3x+6)=123<BR>\n" );
document.write( "6x-3=123<BR>\n" );
document.write( "6x=123+3<BR>\n" );
document.write( "6x=126<BR>\n" );
document.write( "x=126/6<BR>\n" );
document.write( "x=21 for the first number.<BR>\n" );
document.write( "2*21-9=42-9-33 for the second number.<BR>\n" );
document.write( "3*21+6=63+6=69 for the third number.<BR>\n" );
document.write( "proof:<BR>\n" );
document.write( "21+33+69=123<BR>\n" );
document.write( "123=123 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );