document.write( "Question 170345: Two cars leave an intersection. One car travels north; the other east. When the car traveling north had gone 15 mi, the distance between the cars was 5 mi more than the distance traveled by the car heading east. How far had the east bound car traveled? \n" ); document.write( "

Algebra.Com's Answer #125757 by Mathtut(3670) $\"\"$ $\"About$

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label the distance the car going east traveled x and so the distance between the cars would be labeled as x+5. since you have a right triange you can use the pathagorean theorem with one leg 15,the other leg x and the hypothenuse x+5\r
\n" ); document.write( "\n" ); document.write( "so write you equation and solve for x: $\"15%5E2%2Bx%5E2=%28x%2B5%29%5E2\"$
\n" ); document.write( ":
\n" ); document.write( " $\"225%2Bx%5E2=x%5E2%2B10x%2B25\"$
\n" ); document.write( ":
\n" ); document.write( "10x=200
\n" ); document.write( ":
\n" ); document.write( " $\"highlight%28x=20%29\"$ distance the car east traveled
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