document.write( "Question 170300: Hello, I tried to solve the equation 5(square root)x + 1 = 3 by doing 5(sq root) x = 3 and (5(sq. rt.) x) ^ 5 = 3^5 and I my answer is x=243. However, I'm not sure so can you help me please. Thank you \n" ); document.write( "
Algebra.Com's Answer #125713 by checkley77(12844)\"\" \"About 
You can put this solution on YOUR website!
5(square root)x + 1 = 3
\n" ); document.write( "If you mean:
\n" ); document.write( "5sqrt(x)+1=3
\n" ); document.write( "5sqrtx=3-1
\n" ); document.write( "5sqrtx=2
\n" ); document.write( "sqrtx=2/5
\n" ); document.write( "x=(2/5)^2
\n" ); document.write( "x=4/25 ans.
\n" ); document.write( "----------------------------
\n" ); document.write( "OR do you mean:
\n" ); document.write( "5sqrt(x+1)=3
\n" ); document.write( "sqrt(x+1)=3/5
\n" ); document.write( "x+1=(3/5)^2
\n" ); document.write( "x+1=9/25
\n" ); document.write( "x=9/25-1
\n" ); document.write( "x=(9-25)/25
\n" ); document.write( "x=-16/25
\n" ); document.write( "x=-4/5 ans.
\n" ); document.write( "
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