document.write( "Question 170300: Hello, I tried to solve the equation 5(square root)x + 1 = 3 by doing 5(sq root) x = 3 and (5(sq. rt.) x) ^ 5 = 3^5 and I my answer is x=243. However, I'm not sure so can you help me please. Thank you \n" ); document.write( "
Algebra.Com's Answer #125713 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! 5(square root)x + 1 = 3 \n" ); document.write( "If you mean: \n" ); document.write( "5sqrt(x)+1=3 \n" ); document.write( "5sqrtx=3-1 \n" ); document.write( "5sqrtx=2 \n" ); document.write( "sqrtx=2/5 \n" ); document.write( "x=(2/5)^2 \n" ); document.write( "x=4/25 ans. \n" ); document.write( "---------------------------- \n" ); document.write( "OR do you mean: \n" ); document.write( "5sqrt(x+1)=3 \n" ); document.write( "sqrt(x+1)=3/5 \n" ); document.write( "x+1=(3/5)^2 \n" ); document.write( "x+1=9/25 \n" ); document.write( "x=9/25-1 \n" ); document.write( "x=(9-25)/25 \n" ); document.write( "x=-16/25 \n" ); document.write( "x=-4/5 ans. \n" ); document.write( " |