document.write( "Question 2887: I need your help on these three problems....................
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document.write( "(1).
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document.write( "-4 5
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document.write( "-5
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document.write( "The determinant of the matrix A is 1. Find the missing element of the matrix A
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document.write( "a.1
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document.write( "b.3
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document.write( "c.6
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document.write( "d.–24
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document.write( "(2). Find the determinant of the matrix C.
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document.write( "C=
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document.write( "4 0 –7
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document.write( "3 0 6
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document.write( "-5 2 3
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document.write( "a.45
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document.write( "b.24
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document.write( "c.-90
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document.write( "d.-21\r
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document.write( "(3). Use Cramer’s Rule to solve y.
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document.write( "x-4y=4
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document.write( "4x-y=1\r
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document.write( "a.-8/15
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document.write( "b. –1
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document.write( "c. 17/5
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document.write( "d. 0
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document.write( "
Algebra.Com's Answer #1257 by xcentaur(357)![]() ![]() ![]() You can put this solution on YOUR website! [1] \n" ); document.write( "-4 5 \n" ); document.write( "-5 X \n" ); document.write( "\"The determinant of the matrix A is 1.\" \n" ); document.write( " \n" ); document.write( "In matrix X=
\n" ); document.write( "Determinant = ab - cd \n" ); document.write( " \n" ); document.write( "Determinant = (-4*X)-(-5*5) \n" ); document.write( " = -4X+25 \n" ); document.write( "Since we know the determinant is one, \n" ); document.write( "1=-4X+25 \n" ); document.write( "-4X=-24 \n" ); document.write( "X=-24/-4 \n" ); document.write( " =6 \n" ); document.write( "Therefore,correct answer is: c.6 \n" ); document.write( "
\n" ); document.write( "In matrix X of order 3= \n" ); document.write( "
\n" ); document.write( "Determinant of X is= \n" ); document.write( "=x1(y2z3-y3z2)-x2(y1z3-y3z1)+x3(y1z2-z1y2) \n" ); document.write( "Determinant of C is= \n" ); document.write( "= 4[0*3-(2*6)]-0[3*3-(-5*6)]+(-7)[3*2-(-5*0)] \n" ); document.write( "= 4[0-12]-0[9+30]-7[6-0] \n" ); document.write( "= 4[-12]-0[39]-7[6] \n" ); document.write( "= -48-0-42 \n" ); document.write( "= -90 \n" ); document.write( " Therefore,correct answer is: c.-90 \n" ); document.write( "
\r \n" ); document.write( "\n" ); document.write( "detA = p1q2 - p2q1 \n" ); document.write( "=(1*-1)-(4*-4) \n" ); document.write( "=-1-(-16) \n" ); document.write( "=-1+16 \n" ); document.write( "=15 \n" ); document.write( "detY = p1c2 - p2c1 \n" ); document.write( "=(1*1)-(4*4) \n" ); document.write( "=1-16 \n" ); document.write( "=-15 \n" ); document.write( " \n" ); document.write( "By Cramer's Rule,y=detY/detA \n" ); document.write( "y=-15/15 \n" ); document.write( "=-1 \n" ); document.write( " Therefore,the correct answer is: b. –1 \n" ); document.write( "
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