document.write( "Question 2887: I need your help on these three problems....................
\n" ); document.write( "(1).
\n" ); document.write( "-4 5
\n" ); document.write( "-5
\n" ); document.write( "The determinant of the matrix A is 1. Find the missing element of the matrix A
\n" ); document.write( "a.1
\n" ); document.write( "b.3
\n" ); document.write( "c.6
\n" ); document.write( "d.–24
\n" ); document.write( "(2). Find the determinant of the matrix C.
\n" ); document.write( "C=
\n" ); document.write( "4 0 –7
\n" ); document.write( "3 0 6
\n" ); document.write( "-5 2 3
\n" ); document.write( "
\n" ); document.write( "a.45
\n" ); document.write( "b.24
\n" ); document.write( "c.-90
\n" ); document.write( "d.-21\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "(3). Use Cramer’s Rule to solve y.
\n" ); document.write( "x-4y=4
\n" ); document.write( "4x-y=1\r
\n" ); document.write( "\n" ); document.write( "a.-8/15
\n" ); document.write( "b. –1
\n" ); document.write( "c. 17/5
\n" ); document.write( "d. 0
\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #1257 by xcentaur(357)\"\" \"About 
You can put this solution on YOUR website!
[1]
\n" ); document.write( "-4 5
\n" ); document.write( "-5 X
\n" ); document.write( "\"The determinant of the matrix A is 1.\"
\n" ); document.write( "

\n" ); document.write( "In matrix X=\n" ); document.write( "
ab
cd\n" ); document.write( "

\n" ); document.write( "Determinant = ab - cd
\n" ); document.write( "


\n" ); document.write( "Determinant = (-4*X)-(-5*5)
\n" ); document.write( " = -4X+25
\n" ); document.write( "Since we know the determinant is one,
\n" ); document.write( "1=-4X+25
\n" ); document.write( "-4X=-24
\n" ); document.write( "X=-24/-4
\n" ); document.write( " =6
\n" ); document.write( "Therefore,correct answer is: c.6
\n" ); document.write( "


\n" ); document.write( "[2]
\n" ); document.write( "Matrix C=
\n" ); document.write( "\n" ); document.write( "\r\n" ); document.write( "
+40–7 \r\n" ); document.write( "
+30+6\r\n" ); document.write( "
-5+2+3\r\n" ); document.write( "\n" ); document.write( "

\n" ); document.write( "In matrix X of order 3=
\n" ); document.write( "\n" ); document.write( "\r\n" ); document.write( "
x1x2x3 \r\n" ); document.write( "
y1y2y3\r\n" ); document.write( "
z1z2z3\r\n" ); document.write( "\n" ); document.write( "

\n" ); document.write( "Determinant of X is=
\n" ); document.write( "=x1(y2z3-y3z2)-x2(y1z3-y3z1)+x3(y1z2-z1y2)
\n" ); document.write( "Determinant of C is=
\n" ); document.write( "= 4[0*3-(2*6)]-0[3*3-(-5*6)]+(-7)[3*2-(-5*0)]
\n" ); document.write( "= 4[0-12]-0[9+30]-7[6-0]
\n" ); document.write( "= 4[-12]-0[39]-7[6]
\n" ); document.write( "= -48-0-42
\n" ); document.write( "= -90
\n" ); document.write( "
Therefore,correct answer is: c.-90
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\n" ); document.write( "[3]
\n" ); document.write( "Cramer's Rule - Given the system
\n" ); document.write( "p1x + q1y = c1 ... [eqn1]
\n" ); document.write( "p2x + q2y = c2 ... [eqn2]\r
\n" ); document.write( "\n" ); document.write( "Determinant detA = p1q2 - p2q1
\n" ); document.write( "Determinant detX = c1q2 - c2q1
\n" ); document.write( "Determinant detY = p1c2 - p2c1\r
\n" ); document.write( "\n" ); document.write( "Then x=detX/detA
\n" ); document.write( "Then y=detY/detA
\n" ); document.write( "

\n" ); document.write( "Cramer’s Rule to solve y.
\n" ); document.write( "x-4y=4
\n" ); document.write( "4x-y=1
\n" ); document.write( "

\n" ); document.write( "Consider the determinant formed by the x,y and constant term of the given equations.
\n" ); document.write( "\n" ); document.write( "\r\n" ); document.write( "
pqc\r\n" ); document.write( "
+1-44\r\n" ); document.write( "
+4-11\r\n" ); document.write( "\n" ); document.write( "

\r
\n" ); document.write( "\n" ); document.write( "detA = p1q2 - p2q1
\n" ); document.write( "=(1*-1)-(4*-4)
\n" ); document.write( "=-1-(-16)
\n" ); document.write( "=-1+16
\n" ); document.write( "=15
\n" ); document.write( "detY = p1c2 - p2c1
\n" ); document.write( "=(1*1)-(4*4)
\n" ); document.write( "=1-16
\n" ); document.write( "=-15
\n" ); document.write( "

\n" ); document.write( "By Cramer's Rule,y=detY/detA
\n" ); document.write( "y=-15/15
\n" ); document.write( "=-1
\n" ); document.write( "
Therefore,the correct answer is: b. –1
\n" ); document.write( "


\n" ); document.write( "Hope this helps,
\n" ); document.write( "best of luck.
\n" ); document.write( " \n" ); document.write( "

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