document.write( "Question 170266: Help On This Will Be Great Appreciated<3
\n" ); document.write( "Solve The Non-Linear system of Equations. Give Exact Values.
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\n" ); document.write( "\"x%5E2%2By%5E2=10\"
\n" ); document.write( "\"3y=x%5E2%2B8\"
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Algebra.Com's Answer #125692 by Earlsdon(6294)\"\" \"About 
You can put this solution on YOUR website!
Solve:
\n" ); document.write( "\"x%5E2%2By%5E2+=+10\"
\n" ); document.write( "\"3y+=+x%5E2%2B8\" Rewrite this as \"x%5E2+=+3y-8\" and substitute into the 1st equation.
\n" ); document.write( "\"%283y-8%29%2By%5E2+=+10\" Simplify.
\n" ); document.write( "\"y%5E2%2B3y-18+=+0\" Factor.
\n" ); document.write( "\"%28y-3%29%28y%2B6%29+=+0\" Apply the zero product rule.
\n" ); document.write( "\"y+=+3\" or \"y+=+-6\"
\n" ); document.write( "Use the positive solution and substitute into the second equation to solve for x.
\n" ); document.write( "\"3y+=+x%5E2%2B8\" Substitute y = 3.
\n" ); document.write( "\"3%283%29+=+x%5E2%2B8\" Subtract 8 from both sides.
\n" ); document.write( "\"9-8+=+x%5E2\" Take the square root of both sides.
\n" ); document.write( "\"x+=+1\" or \"x+=+-1\"
\n" ); document.write( "The solution consists of two points of intersection:
\n" ); document.write( "(1, 3) and (-1, 3)
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\n" ); document.write( "Just for interest, since we had two solutions for y (y = 3 and y = -6), let's see what happens when we choose the second solution of y = -6 and substitute into the first equation to solve for x.
\n" ); document.write( "\"3y+=+x%5E2%2B8\" Substitute y = -6.
\n" ); document.write( "\"3%28-6%29+=+x%5E2%2B8\" Subtract 8 from both sides.
\n" ); document.write( "\"x%5E2+=+-26\" Take the square root of both sides.
\n" ); document.write( "\"x+=+sqrt%28-26%29\" or \"x+=+-sqrt%28-26%29\" and, as you can see, the results are \"imaginary\" numbers, so there is no \"real\" solution for y = -6.
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\n" ); document.write( "Let's see what the graph of these two functions look like:
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