document.write( "Question 170256: Can someone please explain how to solve the following 2 problems. Any assistance you can provide is greatly appreciated!
\n" ); document.write( "the log of (x+5), base 2 + the log of (x-1), base 2 =4
\n" ); document.write( "and
\n" ); document.write( "the log of 6, base 36 = x
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Algebra.Com's Answer #125690 by Earlsdon(6294)\"\" \"About 
You can put this solution on YOUR website!
Solve for x:
\n" ); document.write( "\"Log%5B2%5D%28x%2B5%29+%2B+Log%5B2%5D%28x-1%29+=+4\" Apply the \"product rule\" (\"Log%5Bb%5D%28M%29%2BLog%5Bb%5D%28N%29+=+Log%5Bb%5D%28M%2AN%29\") for logarithms to the left side.
\n" ); document.write( "\"Log%5B2%5D%28%28x%2B5%29%28x-1%29%29+=+4\" Simplify the argument on the left side.
\n" ); document.write( "\"Log%5B2%5D%28x%5E2%2B4x-5%29+=+4\" Rewrite the left side in its exponential form:(\"Log%5Bb%5D%28x%29+=+y\" means \"b%5Ey+=+x\")
\n" ); document.write( "\"2%5E4+=+x%5E2%2B4x-5\" Simplify.
\n" ); document.write( "\"x%5E2%2B4x-5+=+16\" Subtract 16 from both sides.
\n" ); document.write( "\"x%5E2%2B4x-21+=+0\" Factor this quadratic equation.
\n" ); document.write( "\"%28x-3%29%28x%2B7%29+=+0\" Apply the zero product rule: If A*B = 0, then either A = 0, or B = 0, or both.
\n" ); document.write( "\"x-3+=+0\" or \"x%2B7+=+0\" so that...
\n" ); document.write( "\"x+=+3\" or \"x+=+-7\"
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