document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=170226>Question 170226</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 2.	Find the product of the cube of (-4/3) and square of (-3/2).  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #125662 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=125662\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2. Find the product of the cube of (-4/3) and square of (-3/2). <BR>\n" );
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document.write( "= (-4/3)^3*(-3/2)^2 \r<BR>\n" );
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document.write( "= -64/3^3 * 3^2/4\r<BR>\n" );
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document.write( "Cancel 3^2 in the numerator and the denominator to get:\r<BR>\n" );
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document.write( "= -64/3 * 1/4\r<BR>\n" );
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document.write( "Cancel 4 in the numerator and the denominator to get:\r<BR>\n" );
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document.write( "= -16<BR>\n" );
document.write( "===========<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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