document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=170214>Question 170214</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangle is three times its width. If the perimeter is at most 112 centimeters, what is the greatest possible value for the width? Write an inequality to model the problem.  <BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #125653 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=125653\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Since the perimeter of any rectangle is:<BR>\n" );
document.write( "width + width + length + length<BR>\n" );
document.write( "2(width) + 2(length)<BR>\n" );
document.write( "2(width + length)<BR>\n" );
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document.write( "Let w = width of rectangle<BR>\n" );
document.write( "then because \"length of a rectangle is three times its width\"<BR>\n" );
document.write( "3w = length of rectangle<BR>\n" );
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document.write( "2(width + length) <= 112<BR>\n" );
document.write( "plugging in our variables above:<BR>\n" );
document.write( "2(w + 3w) <= 112<BR>\n" );
document.write( "2(4w) <= 112<BR>\n" );
document.write( "8w <= 112<BR>\n" );
document.write( "w <= 112/8<BR>\n" );
document.write( "w <= 14 centimeters (width)<BR>\n" );
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document.write( "Solution: greatest possible width is 14 centimeters<BR>\n" );
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