document.write( "Question 170217: Trains A and B are travelling in the same direction on parallel tracks. train A is traveling at 40mph and train b is travelling at44mph. Train A passes a station at 9:10 pm and Train B passes the same station @9:40.
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document.write( "At what time will train b cath up with train? \n" );
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Algebra.Com's Answer #125651 by nerdybill(7384)![]() ![]() You can put this solution on YOUR website! Let x = time (in hours) it takes for train B to catch up to train A \n" ); document.write( "Because of the difference in time the two trains passes a station we have: \n" ); document.write( "x + (1/2) = time train A traveled \n" ); document.write( ". \n" ); document.write( "We use the \"distance formula\" \n" ); document.write( "d = rt \n" ); document.write( "where \n" ); document.write( "d is distance traveled \n" ); document.write( "r is rate or speed \n" ); document.write( "t is time \n" ); document.write( ". \n" ); document.write( "For train B to catch up: \n" ); document.write( "\"distance traveled by train A\" = \"distance traveled by train B\" \n" ); document.write( "40(x + (1/2)) = 44x \n" ); document.write( "multiplying both sides by 2: \n" ); document.write( "40(2x + 1) = 88x \n" ); document.write( "80x + 40 = 88x \n" ); document.write( "40 = 8x \n" ); document.write( "5 hours = x \n" ); document.write( ". \n" ); document.write( "But wait, the problem wanted \"clock\" time: \n" ); document.write( "9:40 PM + 5 hours = 2:40 AM \r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |