document.write( "Question 170193: Add. Simplify if possible. 7v/v^2-49 + v/v-7 (this is a fraction)\r
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\n" ); document.write( "\n" ); document.write( "Find the polynomial for the perimeter and for the area z+8 (top of square) z (side of square). \r
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\n" ); document.write( "\n" ); document.write( "Subtract by simiplifying collecting like radical terms if possible 4 square root sign 80 - 6 square root sign 5. \r
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\n" ); document.write( "\n" ); document.write( "If the sides of a square are lengthened by 7cm, the area becomes 196cm^2.
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\n" ); document.write( "\n" ); document.write( "Please help I have to submit by tomorrow.
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Algebra.Com's Answer #125649 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
# 1\r
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\n" ); document.write( "\n" ); document.write( "\"7v%2F%28v%5E2-49%29+%2B+v%2F%28v-7%29\" Start with the given equation\r
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\n" ); document.write( "\n" ); document.write( "\"7v%2F%28%28v-7%29%28v%2B7%29%29+%2B+v%2F%28v-7%29\" Factor the first denominator\r
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\n" ); document.write( "\n" ); document.write( "Take note that the LCD is \"%28v-7%29%28v%2B7%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"7v%2F%28%28v-7%29%28v%2B7%29%29+%2B+%28v%28v%2B7%29%29%2F%28%28v-7%29%28v%2B7%29%29\" Multiply the second fraction by \"%28v%2B7%29%2F%28v%2B7%29\" to make the denominators equal.\r
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\n" ); document.write( "\n" ); document.write( "\"7v%2F%28%28v-7%29%28v%2B7%29%29+%2B+%28v%5E2%2B7v%29%2F%28%28v-7%29%28v%2B7%29%29\" Distribute\r
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\n" ); document.write( "\n" ); document.write( "\"%287v%2Bv%5E2%2B7v%29%2F%28%28v-7%29%28v%2B7%29%29\" Combine the fractions.\r
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\n" ); document.write( "\n" ); document.write( "\"%28v%5E2%2B14v%29%2F%28%28v-7%29%28v%2B7%29%29\" Combine like terms.\r
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\n" ); document.write( "\n" ); document.write( "\"%28v%5E2%2B14v%29%2F%28v%5E2-49%29\" FOIL the denominator.\r
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\n" ); document.write( "\n" ); document.write( "So \"7v%2F%28v%5E2-49%29+%2B+v%2F%28v-7%29\" simplifies to \"%28v%5E2%2B14v%29%2F%28v%5E2-49%29\" \r
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\n" ); document.write( "\n" ); document.write( "Area: \"A=Length%2AWidth=z%28z%2B8%29=z%5E2%2B8z\"\r
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\n" ); document.write( "\n" ); document.write( "So the area is \"A=z%5E2%2B8z\" square units\r
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\n" ); document.write( "\n" ); document.write( "Perimeter: \"P=2%2Alength%2B2%2Awidth=2%28z%29%2B2%28z%2B8%29=2z%2B2z%2B16=4z%2B16\"\r
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\n" ); document.write( "\n" ); document.write( "So the perimeter is \"P=4z%2B16\" units\r
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\n" ); document.write( "\n" ); document.write( "# 3\r
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\n" ); document.write( "\n" ); document.write( "\"sqrt%2880%29-6%2Asqrt%285%29\" Start with the given expression\r
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\n" ); document.write( "\n" ); document.write( "\"4%2Asqrt%285%29-6%2Asqrt%285%29\" Simplify \"sqrt%2880%29\" to get \"4%2Asqrt%285%29\". Note: If you need help with simplifying square roots, check out this solver.\r
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\n" ); document.write( "\n" ); document.write( "Since we have the common term \"sqrt%285%29\", we can combine like terms\r
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\n" ); document.write( "\n" ); document.write( "\"%284-6%29sqrt%285%29\" Combine like terms. Remember, \"5x%2B3x-4x=%285%2B3-4%29x=4x\"\r
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\n" ); document.write( "\n" ); document.write( "\"-2%2Asqrt%285%29\" Now simplify \"4-6\" to get \"-2\"\r
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\n" ); document.write( "\n" ); document.write( "So \"sqrt%2880%29-6%2Asqrt%285%29\" simplifies to \"-2%2Asqrt%285%29\". \r
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\n" ); document.write( "\n" ); document.write( "In other words, \"sqrt%2880%29-6%2Asqrt%285%29=-2%2Asqrt%285%29\"\r
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\n" ); document.write( "\n" ); document.write( "# 4\r
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\n" ); document.write( "\n" ); document.write( "Area of original square \"A%5B1%5D=s%5E2\"\r
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\n" ); document.write( "\n" ); document.write( "Area of new square: \"A%5B2%5D=%28s%2B7%29%5E2\"\r
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\n" ); document.write( "\n" ); document.write( "Since the \"area becomes 196cm^2\", this means that \"A%5B2%5D=196\"\r
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\n" ); document.write( "\n" ); document.write( "\"A%5B2%5D=%28s%2B7%29%5E2\" Start with the second equation\r
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\n" ); document.write( "\n" ); document.write( "\"196=%28s%2B7%29%5E2\" Plug in \"A%5B2%5D=196\"\r
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\n" ); document.write( "\n" ); document.write( "\"196=s%5E2%2B14s%2B49\" FOIL\r
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\n" ); document.write( "\n" ); document.write( "\"0=s%5E2%2B14s%2B49-196\" Subtract 196 from both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"0=s%5E2%2B14s-147\" Combine like terms.\r
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\n" ); document.write( "\n" ); document.write( "Notice we have a quadratic equation in the form of \"as%5E2%2Bbs%2Bc\" where \"a=1\", \"b=14\", and \"c=-147\"\r
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\n" ); document.write( "\n" ); document.write( "Let's use the quadratic formula to solve for s\r
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\n" ); document.write( "\n" ); document.write( "\"s+=+%28-b+%2B-+sqrt%28+b%5E2-4ac+%29%29%2F%282a%29\" Start with the quadratic formula\r
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\n" ); document.write( "\n" ); document.write( "\"s+=+%28-%2814%29+%2B-+sqrt%28+%2814%29%5E2-4%281%29%28-147%29+%29%29%2F%282%281%29%29\" Plug in \"a=1\", \"b=14\", and \"c=-147\"\r
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\n" ); document.write( "\n" ); document.write( "\"s+=+%28-14+%2B-+sqrt%28+196-4%281%29%28-147%29+%29%29%2F%282%281%29%29\" Square \"14\" to get \"196\". \r
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\n" ); document.write( "\n" ); document.write( "\"s+=+%28-14+%2B-+sqrt%28+196--588+%29%29%2F%282%281%29%29\" Multiply \"4%281%29%28-147%29\" to get \"-588\"\r
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\n" ); document.write( "\n" ); document.write( "\"s+=+%28-14+%2B-+sqrt%28+196%2B588+%29%29%2F%282%281%29%29\" Rewrite \"sqrt%28196--588%29\" as \"sqrt%28196%2B588%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"s+=+%28-14+%2B-+sqrt%28+784+%29%29%2F%282%281%29%29\" Add \"196\" to \"588\" to get \"784\"\r
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\n" ); document.write( "\n" ); document.write( "\"s+=+%28-14+%2B-+sqrt%28+784+%29%29%2F%282%29\" Multiply \"2\" and \"1\" to get \"2\". \r
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\n" ); document.write( "\n" ); document.write( "\"s+=+%28-14+%2B-+28%29%2F%282%29\" Take the square root of \"784\" to get \"28\". \r
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\n" ); document.write( "\n" ); document.write( "\"s+=+%28-14+%2B+28%29%2F%282%29\" or \"s+=+%28-14+-+28%29%2F%282%29\" Break up the expression. \r
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\n" ); document.write( "\n" ); document.write( "\"s+=+%2814%29%2F%282%29\" or \"s+=++%28-42%29%2F%282%29\" Combine like terms. \r
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\n" ); document.write( "\n" ); document.write( "\"s+=+7\" or \"s+=+-21\" Simplify. \r
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\n" ); document.write( "\n" ); document.write( "So the possible answers are \"s+=+7\" or \"s+=+-21\" \r
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\n" ); document.write( "\n" ); document.write( "However, since a negative side length is NOT possible, this means that the only answer is \"s+=+7\"\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So the original side length is 7 centimeters
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