document.write( "Question 170210: find three consecutive odd integers such that the squar of the thid integer plus the product of the other two integers is 268. \n" ); document.write( "
Algebra.Com's Answer #125648 by nerdybill(7384)\"\" \"About 
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find three consecutive odd integers such that the squar of the thid integer plus the product of the other two integers is 268.
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\n" ); document.write( "Let x = first consecutive odd integer
\n" ); document.write( "then
\n" ); document.write( "x+2 = second consecutive odd integer
\n" ); document.write( "x+4 = third consecutive odd integer
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\n" ); document.write( "From:\"the square of the third integer plus the product of the other two integers is 268\" we get:
\n" ); document.write( "(x+4)^2 + x(x+2) = 268
\n" ); document.write( "x^2+8x+16 + x^2+2x = 268
\n" ); document.write( "2x^2 + 10x + 16 = 268
\n" ); document.write( "x^2 + 5x + 8 = 134
\n" ); document.write( "x^2 + 5x - 126 = 0
\n" ); document.write( "(x-9)(x+14) = 0
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\n" ); document.write( "x = {9, -14}
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\n" ); document.write( "We can toss out the -14, leaving us with:
\n" ); document.write( "x=9
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\n" ); document.write( "Solution:
\n" ); document.write( "9, 11, 13 \n" ); document.write( "
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