document.write( "Question 170205: Thanks so much for all the help!!! I have one last one that I think I have some clue about but not sure:\r
\n" ); document.write( "\n" ); document.write( "A man is carrying rice on a journey. He passes through three custom stations. At the first he gives up 1/3 of his rice; at the second he is allowed to keep 1/3 of what is left; at the third he gives up 1/4 of what remains. After passing through all three custom stations, he has 6 pounds less than he started with. How much rice did he have when he started?
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Algebra.Com's Answer #125643 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
Let x=amount of rice he starts with and y=amount he has leftover\r
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After First Station

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\n" ); document.write( "\n" ); document.write( "Since \"At the first he gives up 1/3 of his rice\", this tells us that after the first station, he has \"x-%281%2F3%29x\" pounds of rice leftover\r
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\n" ); document.write( "\n" ); document.write( "Note: I've subtracted 1/3 of the amount \"x\" from \"x\"\r
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\n" ); document.write( "\n" ); document.write( "Combine like terms to get \"%282%2F3%29x\". So he has \"%282%2F3%29x\" pounds of rice leftover after the first station (this makes sense because the guard took 1/3 so the man must have 2/3 leftover).\r
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\n" ); document.write( "\n" ); document.write( "Note: remember, the \"x\" is just a number (a number in which we do NOT know). However, to help you get an idea of what is going on, let \"x=12\" (ie let's say that he started at 12 lbs of rice). After the first station, he would have \"%282%2F3%2912=24%2F3=8\" lbs of rice.\r
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After Second Station

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\n" ); document.write( "\n" ); document.write( "Keep in mind that the man still has \"%282%2F3%29x\" lbs of rice. \r
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\n" ); document.write( "\n" ); document.write( "Since at \"the second he is allowed to keep 1/3 of what is left\", this means that they will take 2/3 of what he has left. \r
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\n" ); document.write( "\n" ); document.write( "So this means that you need to subtract like this\r
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\n" ); document.write( "\n" ); document.write( "Amount he has left - (2/3)*(Amount he has left )\r
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\n" ); document.write( "\n" ); document.write( "\"%282%2F3%29x+-+%282%2F3%29%2A%28%282%2F3%29x%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"%282%2F3%29x+-+%284%2F9%29x\" Multiply\r
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\n" ); document.write( "\n" ); document.write( "\"%282%2F9%29x\" Combine the fractions.\r
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\n" ); document.write( "\n" ); document.write( "So after the second station, he has \"%282%2F9%29x\" lbs of rice left.\r
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After Third Station

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\n" ); document.write( "\n" ); document.write( "Finally, because \"at the third he gives up 1/4 of what remains\", this tells us that we subtract 1/4 of what he has left like this:\r
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\n" ); document.write( "\n" ); document.write( "Amount he has left - (1/4)*(Amount he has left )\r
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\n" ); document.write( "\n" ); document.write( "Which algebraically looks like:\r
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\n" ); document.write( "\n" ); document.write( "\"%282%2F9%29x-%281%2F4%29%28%282%2F9%29x%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"%282%2F9%29x-%281%2F18%29x\" Multiply\r
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\n" ); document.write( "\n" ); document.write( "\"%281%2F6%29x\" Combine the fractions.\r
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\n" ); document.write( "\n" ); document.write( "So after the third station, he has \"%281%2F6%29x\" lbs of rice left.\r
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\n" ); document.write( "\n" ); document.write( "Since \"he has 6 pounds less than he started with.\" this means that he ended up with \"x-6\" lbs. Also, we know that he ended up with \"%281%2F6%29x\" lbs of rice (after passing through the third station)\r
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\n" ); document.write( "\n" ); document.write( "So this means that the two are equal, so...\r
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\n" ); document.write( "\n" ); document.write( "\"x-6=%281%2F6%29x\"\r
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\n" ); document.write( "\n" ); document.write( "\"6x-36=x\" Multiply EVERY term by the LCD 6 to clear the fraction.\r
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\n" ); document.write( "\n" ); document.write( "\"6x=x%2B36\" Add \"36\" to both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"6x-x=36\" Subtract \"x\" from both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"5x=36\" Combine like terms on the left side.\r
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\n" ); document.write( "\n" ); document.write( "\"x=%2836%29%2F%285%29\" Divide both sides by \"5\" to isolate \"x\".\r
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\n" ); document.write( "\n" ); document.write( "\"x=7.2\" Divide.\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So the man started with 7.2 lbs of rice and the amounts after each station are:\r
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\n" ); document.write( "\n" ); document.write( "1st station: \"%282%2F3%29%287.2%29=4.8\" so he had 4.8 lbs after the 1st station\r
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\n" ); document.write( "\n" ); document.write( "2nd station: \"%282%2F9%29%287.2%29=1.6\" so he had 1.6 lbs after the 2nd station\r
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\n" ); document.write( "\n" ); document.write( "3rd station: \"%281%2F6%29%287.2%29=1.2\" so he had 1.2 lbs after the 3rd station\r
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\n" ); document.write( "\n" ); document.write( "Since the difference between 7.2 and 1.2 is \"7.2-1.2=6\" this helps confirm our answer.\r
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