document.write( "Question 170144: I'm attempting to do corrections on a test, but these three questions are giving me trouble! I've tried several different things, and I keep coming up with the same (wrong!) answer!\r
\n" ); document.write( "\n" ); document.write( "1) If \"x\" is an angle in quadrant 4 and \"Cot%28x%29=+-7%2F24\", find the value of \"Sin\"\"1%2F2\"\"x\".\r
\n" ); document.write( "\n" ); document.write( "2) What is the solution set of the equation\r
\n" ); document.write( "\n" ); document.write( " \"Sin%282x%29+-+Cos%5E2x%2B1+\" = \"+Sin%5E2x%2B+Sin%28x%29+\" in the interval \"0%3C=x%3C2pi\"?\r
\n" ); document.write( "\n" ); document.write( "3) Find the solution set of \"6Sin%28x%29+%2B+11=+2Csc%28x%29\" over the domain \"0%3Cx%3C360\"°.
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Algebra.Com's Answer #125607 by Edwin McCravy(20060)\"\" \"About 
You can put this solution on YOUR website!
Stanbon's solution is correct but he does not do problem 2 and he does not explain why we know to take the positive square root in 1.\r
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document.write( "1) If \"x\" is an angle in quadrant 4 and \"Cot%28x%29=+-7%2F24\", find the value of \"Sin\"\"1%2F2\"\"x\".\r\n" );
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document.write( "Since this involves drawing a graph in which \"x\" represents\r\n" );
document.write( "the horizontal axis, not an angle,  I will temporarily change\r\n" );
document.write( "\"x\" to \"alpha%29\" to avoid a conflict of letters.  Change\r\n" );
document.write( "the problem to read this way:\r\n" );
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document.write( "1) If \"alpha\" is an angle in quadrant 4 and \"Cot%28alpha%29=+-7%2F24\", find the value of \"Sin\"\"1%2F2\"\"alpha\".\r\n" );
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document.write( "We must use the identity:\r\n" );
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document.write( "\"Sin\"\"1%2F2\"\"alpha\"\"%22=%22\"\"%22%22%2B-sqrt%28%281-Cos%28alpha%29%29%2F2%29\"\r\n" );
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document.write( "However we do not know \"Cos%28alpha%29\"\r\n" );
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document.write( "So we must first draw the picture of the angle \"alpha\":\r\n" );
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document.write( "We know that \"Cot%28alpha%29\" is by definition \"x%2Fy\", we\r\n" );
document.write( "can draw the angle in the 4th quadrant with referent angle\r\n" );
document.write( "is inside a triangle whose horizontal side \"x\" is taken\r\n" );
document.write( "to be the numerator of \"-7%2F24\", considered positive because\r\n" );
document.write( "it goes right of the y-axis, and whose vertical side \"y\" is taken as \r\n" );
document.write( "the denominator \"-24\", taken negative because it goes down\r\n" );
document.write( "below the x-axis: \r\n" );
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document.write( " \r\n" );
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document.write( "Next we calculate \"r\" by the Pythagorean theorem:\r\n" );
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document.write( "\"r%5E2=x%5E2%2By%5E2\"\r\n" );
document.write( "\"r%5E2=%287%29%5E2%2B%28-24%29%5E2\"\r\n" );
document.write( "\"r%5E2=49%2B576\"\r\n" );
document.write( "\"r%5E2=625\"\r\n" );
document.write( "\"r=sqrt%28625%29\"\r\n" );
document.write( "\"r=25\"\r\n" );
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document.write( "So we label the slanted line segment \"r=25\". \r\n" );
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document.write( " \r\n" );
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document.write( "Now we can find \"Cos%28alpha%29\"\r\n" );
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document.write( "\"Cos%28alpha%29=x%2Fr=7%2F25\"\r\n" );
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document.write( "So we substitute \"7%2F25\" for \"Cos%28alpha%29\" in\r\n" );
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document.write( "\"Sin\"\"1%2F2\"\"alpha\"\"%22=%22\"\"%22%22%2B-sqrt%28%281-Cos%28alpha%29%29%2F2%29\"\r\n" );
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document.write( "\"Sin\"\"1%2F2\"\"alpha\"\"%22=%22\"\"%22%22%2B-sqrt%28%281-7%2F25%29%2F2%29\"\r\n" );
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document.write( "\"Sin\"\"1%2F2\"\"alpha\"\"%22=%22\"\"%22%22%2B-sqrt%28%2825%2F25-7%2F25%29%2F2%29\"\r\n" );
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document.write( "\"Sin\"\"1%2F2\"\"alpha\"\"%22=%22\"\"%22%22%2B-sqrt%28%2818%2F25%29%2F2%29\"\r\n" );
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document.write( "\"Sin\"\"1%2F2\"\"alpha\"\"%22=%22\"\"%22%22%2B-sqrt%28%2818%2F25%29%281%2F2%29%29\"\r\n" );
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document.write( "\"Sin\"\"1%2F2\"\"alpha\"\"%22=%22\"\"%22%22%2B-sqrt%289%2F25%29\"\r\n" );
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document.write( "\"Sin\"\"1%2F2\"\"alpha\"\"%22=%22\"±\"3%2F5\"\r\n" );
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document.write( "Next we must decide whether this is positive or negative:\r\n" );
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document.write( "Since \"alpha\" is is the 4th quadrant, then \r\n" );
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document.write( "\"270%3Calpha%3C360\"° so multiplying that through by \"1%2F2\"\r\n" );
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document.write( "\"135%3C1%2F2\"\"alpha%3C180\"° \r\n" );
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document.write( "The means \"1%2F2\"\"alpha\" is in quadrant 2.  Since\r\n" );
document.write( "the sine is positive in the 2nd quadrant, the final answer\r\n" );
document.write( "is \r\n" );
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document.write( "\"Sin\"\"1%2F2\"\"alpha=3%2F5\" \r\n" );
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document.write( "And of course now that we have the answer we can change\r\n" );
document.write( "\"alpha\" back to \"x\":\r\n" );
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document.write( "\"Sin\"\"1%2F2\"\"x=3%2F5\"\r\n" );
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document.write( "2) What is the solution set of the equation\r\n" );
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document.write( " \"Sin%282x%29+-+Cos%5E2x%2B1+\" = \"+Sin%5E2x%2B+Sin%28x%29+\" in the interval \"0%3C=x%3C2pi\"?\r\n" );
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document.write( "Use the identity \"Cos%5E2x=+1-Sin%5E2x\" to replace \"Cos%5E2x\" on the\r\n" );
document.write( "left side:\r\n" );
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document.write( " \"Sin%282x%29+-+%281-Sin%5E2x%29+%2B1+\" = \"+Sin%5E2x%2B+Sin%28x%29+\"\r\n" );
document.write( "\r\n" );
document.write( " \"Sin%282x%29+-+1%2BSin%5E2x+%2B1+\" = \"+Sin%5E2x%2B+Sin%28x%29+\"\r\n" );
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document.write( "\"Sin%282x%29+%2BSin%5E2x+\" = \"+Sin%5E2x%2B+Sin%28x%29+\"\r\n" );
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document.write( "\"Sin%282x%29++\" = \"+Sin%28x%29+\"\r\n" );
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document.write( "\"Sin%282x%29+-+Sin%28x%29\" = \"0\"\r\n" );
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document.write( "Now use identity \"Sin%282x%29+=+2%2ASin%28x%29Cos%28x%29\" to\r\n" );
document.write( "replace \"Sin%282x%29\"\r\n" );
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document.write( "\"2%2ASin%28x%29Cos%28x%29+-+Sin%28x%29\" = \"0\"\r\n" );
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document.write( "Factor out \"Sin%28x%29\"\r\n" );
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document.write( "\"Sin%28x%29%282Cos%28x%29+-+1%29\" = \"0\"\r\n" );
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document.write( "Use the zero-factor principle:\r\n" );
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document.write( "3) Find the solution set of \"6Sin%28x%29+%2B+11=+2Csc%28x%29\" over the domain \"0%3Cx%3C360\"°.\r\n" );
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document.write( "\"6Sin%28x%29+%2B+11=+2Csc%28x%29\"\r\n" );
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document.write( "Use identity \"Csc%28x%29=1%2FSin%28x%29\"\r\n" );
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document.write( "\"6Sin%28x%29+%2B+11=+2%281%2FSin%28x%29%29\"\r\n" );
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document.write( "Multiply through by \"Sin%28x%29\"\r\n" );
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document.write( "\"6Sin%5E2x%2B11Sin%28x%29=2\"\r\n" );
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document.write( "\"6Sin%5Ex%2B11Sin%28x%29-2=0\"\r\n" );
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document.write( "\"%286Sin%28x%29-1%29%28Sin%28x%29%2B2%29=0\"\r\n" );
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document.write( "Use the zero-factor principle:\r\n" );
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document.write( "Edwin

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