document.write( "Question 170164: I have such a hard time doing this problem: Write Standard Equation of Parabola, Given Focus: (-2,3)and Directrix: x=2. \n" ); document.write( "
Algebra.Com's Answer #125604 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
First we need to find the vertex:\r
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\n" ); document.write( "\n" ); document.write( "X-coordinate of the vertex: Simply average the x coordinate of the focus (-2) with the directix (2) to get \"%28-2%2B2%29%2F2=0%2F2=0\"\r
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\n" ); document.write( "\n" ); document.write( "So the x-coordinate of the vertex is \"x=0\". This means that \"h=0\"\r
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\n" ); document.write( "\n" ); document.write( "Y-coordinate of the vertex: This value is equal to the y-coordinate of the focus. So the y-coordinate of the vertex is \"y=3\". This means that \"k=3\"\r
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\n" ); document.write( "\n" ); document.write( "So the vertex is (0,3)\r
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\n" ); document.write( "\n" ); document.write( "Now that we have the vertex, we can use that to find the distance from the focus to the vertex.\r
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\n" ); document.write( "\n" ); document.write( "Since the focus (-2,3) is 2 units from the vertex (0,3), this means that \"p=2\"\r
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\n" ); document.write( "\n" ); document.write( "Now let's find the equation:\r
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\n" ); document.write( "\n" ); document.write( "Since the focus is (-2,3) and the directrix is x=2, this means that the parabola is opening to the left like this\r
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\n" ); document.write( "\n" ); document.write( "\"Photobucket\r
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\n" ); document.write( "\n" ); document.write( "\"-4p%28x-h%29=%28y-k%29%5E2\" Start with the standard equation (for parabolas that open up to the left)\r
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\n" ); document.write( "\n" ); document.write( "\"-4%282%29%28x-0%29=%28y-3%29%5E2\" Plug in \"p=2\", \"h=0\", and \"k=3\"\r
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\n" ); document.write( "\n" ); document.write( "\"-8%28x-0%29=%28y-3%29%5E2\" Multiply\r
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\n" ); document.write( "\n" ); document.write( "So the standard equation is \"-8%28x-0%29=%28y-3%29%5E2\"
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