document.write( "Question 170159: Using AX=BY+C
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Algebra.Com's Answer #125602 by jim_thompson5910(35256)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "\"x-2y=4\" Start with the given equation.\r
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\n" ); document.write( "\n" ); document.write( "\"-2y=4-x\" Subtract \"x\" from both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"-2y=-x%2B4\" Rearrange the terms.\r
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\n" ); document.write( "\n" ); document.write( "\"y=%28-x%2B4%29%2F%28-2%29\" Divide both sides by \"-2\" to isolate y.\r
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\n" ); document.write( "\n" ); document.write( "\"y=%28%28-1%29%2F%28-2%29%29x%2B%284%29%2F%28-2%29\" Break up the fraction.\r
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\n" ); document.write( "\n" ); document.write( "\"y=%281%2F2%29x-2\" Reduce.\r
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\n" ); document.write( "\n" ); document.write( "Looking at \"y=%281%2F2%29x-2\" we can see that the equation is in slope-intercept form \"y=mx%2Bb\" where the slope is \"m=1%2F2\" and the y-intercept is \"b=-2\" \r
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\n" ); document.write( "\n" ); document.write( "Since \"b=-2\" this tells us that the y-intercept is .Remember the y-intercept is the point where the graph intersects with the y-axis\r
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\n" ); document.write( "\n" ); document.write( "Now since the slope is comprised of the \"rise\" over the \"run\" this means\r
\n" ); document.write( "\n" ); document.write( "\"slope=rise%2Frun\"\r
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\n" ); document.write( "\n" ); document.write( "Also, because the slope is \"1%2F2\", this means:\r
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\n" ); document.write( "\n" ); document.write( "\"rise%2Frun=1%2F2\"\r
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\n" ); document.write( "\n" ); document.write( "which shows us that the rise is 1 and the run is 2. This means that to go from point to point, we can go up 1 and over 2\r
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\n" ); document.write( "\n" ); document.write( "So starting at , go up 1 unit \r
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\n" ); document.write( "\n" ); document.write( "and to the right 2 units to get to the next point \r
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\n" ); document.write( "\n" ); document.write( "Now draw a line through these points to graph \"y=%281%2F2%29x-2\"\r
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\n" ); document.write( "\n" ); document.write( " So this is the graph of \"y=%281%2F2%29x-2\" through the points and
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