document.write( "Question 170131: my problem reads, write the standard equation of each vertex, and these are the problems they give me\r
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document.write( "1. y^2-8y-8x+64=0\r
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document.write( "2. 36x^2-288x+25y^2-150y=99 \n" );
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Algebra.Com's Answer #125596 by stanbon(75887) ![]() You can put this solution on YOUR website! write the standard equation of each vertex, and these are the problems they give me \n" ); document.write( "1. y^2-8y-8x+64=0 \n" ); document.write( "Complete the square on the y-terms: \n" ); document.write( "y^2-8y+16 =8x-64+16 \n" ); document.write( "(y-4)^2 = 8x-48 \n" ); document.write( "(y-4)^2 = 8(x-6) \n" ); document.write( "The vertex is (6,4) \n" ); document.write( "---------------------------\r \n" ); document.write( "\n" ); document.write( "2. 36x^2-288x+25y^2-150y=99 \n" ); document.write( "Complete the square on the x and on the y-terms: \n" ); document.write( "36x^2-288x+? + 25y^2-150y+? = -99+? \n" ); document.write( "36(x^2- 8x + 16) + 25(y^2 - 6y + 9) = -99 + 36*16 + 25*9 \n" ); document.write( "36(x-4)^2 + 25(y-3)^2 = 702 \n" ); document.write( "Divide thru by 702 to get: \n" ); document.write( "(x-4)^2/19.5 + (y-3)^2/28.08 = 1 \n" ); document.write( "------------------------------ \n" ); document.write( "center at (4,3) \n" ); document.write( "vertices at (4,3+sqrt(28.08)) and (4(3-sqrt(28.08)) \n" ); document.write( "========================================= \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " \n" ); document.write( " |