document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=170136>Question 170136</A>: <I><SPAN STYLE=\"word-break: break-all;\"> im familar with writing conic sections in there standard equation but there are 2 questions that have me stumped in peticular.here is one of them. <BR>\n" );
document.write( "y^2-8y-8x+64=0 <BR>\n" );
document.write( "and im suppose to write this in its standard equation. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #125584 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=125584\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> this is a parabola where the x and y have been \"swaped\"\r<BR>\n" );
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document.write( "the axis of symmetry is horizontal instead of vertical __ parabola opens to the right (positive x)\r<BR>\n" );
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document.write( "adding 8x-64 __ y^2-8y=8x-64\r<BR>\n" );
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document.write( "completing the square __ y^2-8y+16=8x-48\r<BR>\n" );
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document.write( "multiplying by 1/8 __ (1/8)(y-4)^2=x-6\r<BR>\n" );
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document.write( "adding 6 __ (1/8)(y-4)^2 + 6 = x __ this is the vertex form\r<BR>\n" );
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document.write( "standard form __ x = (1/8)y^2 - y + 8 </SPAN>\n" );
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