document.write( "Question 170139This question is from textbook intermediate algebra
\n" ); document.write( ": 90) 3^2x -8 . 3^x +15=0
\n" ); document.write( "94) If x= (log125 5)^log5 125\r
\n" ); document.write( "\n" ); document.write( " Please help me to solve this two. Thank You
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Algebra.Com's Answer #125575 by stanbon(75887)\"\" \"About 
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90) 3^2x -8(3^x) +15=0
\n" ); document.write( "Let w = 3^x
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\n" ); document.write( "Rewrite the quadratic equation:
\n" ); document.write( "w^2 - 8w + 15 = 0
\n" ); document.write( "(w-5)(w-3) = 0
\n" ); document.write( "w = 3 or w = 5
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\n" ); document.write( "Solve for x:
\n" ); document.write( "3^x = 3 or 3^x = 5
\n" ); document.write( "x = 1 or x = [log5/log3] = 1.4649735...
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\n" ); document.write( "\n" ); document.write( "94) If x= (log125 5)^log5 125
\n" ); document.write( "log125 5 = log(5)/log(125) = 1/3
\n" ); document.write( "log5 125 = 3
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\n" ); document.write( "Therefore x = (1/3)3 = 1
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.\r
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