document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=170128>Question 170128</A>: <I><SPAN STYLE=\"word-break: break-all;\"> im familar with writing conic sections in there standard equation but there are 2 questions that have me stumped in peticular.here is one of them.\r<BR>\n" );
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document.write( "y^2-8y-8x+64=0\r<BR>\n" );
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document.write( "and im suppose to write this in standard form<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #125560 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=125560\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> y^2-8y-8x+64=0 <BR>\n" );
document.write( "and I'm supposed to write this in standard form<BR>\n" );
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document.write( "Complete the square of the y terms, as follows:<BR>\n" );
document.write( "y^2 - 8y + 16 = 8x -64 + 16<BR>\n" );
document.write( "(y-4)^2 = 8x - 48<BR>\n" );
document.write( "(y-4)^2 = 8(x-6)<BR>\n" );
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document.write( "This form shows you the vertex is at (6,4) and the <BR>\n" );
document.write( "focus of the parabola is 8/4 = 2 units above the vertex.<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.\r<BR>\n" );
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