document.write( "Question 23797: Suppose that the length of a certain rectangle is 2 cm more than three times its width. If the area of the rectangleis 56 square centimeters, find its length and width. \n" ); document.write( "

Algebra.Com's Answer #12550 by Paul(988) $\"\"$ $\"About$

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let the length be y and let the width be x
\n" ); document.write( "y = 3x+2\r
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\n" ); document.write( "\n" ); document.write( "Area = length x width
\n" ); document.write( "xy=56
\n" ); document.write( "x(3x+2)=56
\n" ); document.write( " $\"3x%5E2%2B2x=56\"$
\n" ); document.write( " $\"3x%5E2%2B2x-56=0\"$ --- solve for x by using quardratic formula:
\n" ); document.write( " $\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"$
\n" ); document.write( "In $\"ax%5E2+%2B+bx+%2B+c+=+0\"$ a=3, b=2, c=-56
\n" ); document.write( " $\"x+=+%28-2+%2B-+sqrt%28+%282%29%5E2-4%2A3%2A-56+%29%29%29%2F+2%283%29\"$ ---> divide by 2(3)
\n" ); document.write( " $\"x+=+%28-2+%2B-+sqrt%28+4%2B672%29%29%2F6%29\"$
\n" ); document.write( " $\"x+=+%28-2+%2B+sqrt%28+676%29%29%2F6%29\"$ ---> add the foloowing don't subtrract.
\n" ); document.write( "x = 4
\n" ); document.write( "3(4)+2 = 14
\n" ); document.write( "Hence, the length is 14 and the width is 4.
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