document.write( "Question 170026: Toxic pollutants. The annual cost in dollars for removing
\n" ); document.write( "p% of the toxic chemicals from a town’s water supply is
\n" ); document.write( "given by the formula
\n" ); document.write( "C(p) = 500,00/ 100-p
\n" ); document.write( ".
\n" ); document.write( "a) Use the accompanying graph to estimate the cost for
\n" ); document.write( "removing 90% and 95% of the toxic chemicals.
\n" ); document.write( "b) Use the formula to find C(99.5) and C(99.9).
\n" ); document.write( "c) What happens to the cost as the percentage of
\n" ); document.write( "pollutants removed approaches 100%? \n" ); document.write( "

Algebra.Com's Answer #125488 by checkley77(12844) $\"\"$ $\"About$

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C(p) = 500,00[0]/(100-p) I'LL ASSUME YOU LEFT OUR THE LAST 0 IN 500,000 FIGURE.
\n" ); document.write( "C(90)=500,000/(100-90)
\n" ); document.write( "C(90)=500,000/10
\n" ); document.write( "C(90)=50,000 ANS.
\n" ); document.write( "C(95)=500,000/(100-95)
\n" ); document.write( "C(95)=500,000/5
\n" ); document.write( "C(95)=100,000 ANS.
\n" ); document.write( "C(99.5)=500,000/(100-99.5)
\n" ); document.write( "C(99.5)=500,000/.5
\n" ); document.write( "C(99.5)=1,000,000 ANS.
\n" ); document.write( "C(99.9)=500,000/(100-99.9)
\n" ); document.write( "C(99.9)=500,00/.1
\n" ); document.write( "C(99.9)=5,000,000 ANS.
\n" ); document.write( "AS P APPROACHES 100% THE COST APPROACHES INFINITY.
\n" ); document.write( " \n" ); document.write( "

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