document.write( "Question 170017: where do I begin with this problem?
\n" ); document.write( "xsq+3x=4
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Algebra.Com's Answer #125478 by midwood_trail(310)\"\" \"About 
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x^2+ 3x = 4\r
\n" ); document.write( "\n" ); document.write( "Begin by subtracting 4 from both sides and equating to zero.\r
\n" ); document.write( "\n" ); document.write( "x^2 + 3x - 4 = 0\r
\n" ); document.write( "\n" ); document.write( "We now factor the left side.\r
\n" ); document.write( "\n" ); document.write( "x^2 + 3x - 4 becomes (x - 1)(x + 4).\r
\n" ); document.write( "\n" ); document.write( "We now set each factor to zero and solve for x.\r
\n" ); document.write( "\n" ); document.write( "x - 1 = 0\r
\n" ); document.write( "\n" ); document.write( "x = 1\r
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\n" ); document.write( "\n" ); document.write( "x + 4 = 0\r
\n" ); document.write( "\n" ); document.write( "x = -4\r
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\n" ); document.write( "\n" ); document.write( "Final answer: x = 1 and x = -4\r
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