document.write( "Question 170017: where do I begin with this problem?
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document.write( "xsq+3x=4 \n" );
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Algebra.Com's Answer #125478 by midwood_trail(310)![]() ![]() ![]() You can put this solution on YOUR website! x^2+ 3x = 4\r \n" ); document.write( "\n" ); document.write( "Begin by subtracting 4 from both sides and equating to zero.\r \n" ); document.write( "\n" ); document.write( "x^2 + 3x - 4 = 0\r \n" ); document.write( "\n" ); document.write( "We now factor the left side.\r \n" ); document.write( "\n" ); document.write( "x^2 + 3x - 4 becomes (x - 1)(x + 4).\r \n" ); document.write( "\n" ); document.write( "We now set each factor to zero and solve for x.\r \n" ); document.write( "\n" ); document.write( "x - 1 = 0\r \n" ); document.write( "\n" ); document.write( "x = 1\r \n" ); document.write( "\n" ); document.write( "=========\r \n" ); document.write( "\n" ); document.write( "x + 4 = 0\r \n" ); document.write( "\n" ); document.write( "x = -4\r \n" ); document.write( "\n" ); document.write( "=========\r \n" ); document.write( "\n" ); document.write( "Final answer: x = 1 and x = -4\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |