document.write( "Question 170004: A parabolic satellite television antenna has a diameter of 6 feet and is 1.6 feet deep. How far is the focus from the vertex?\r
\n" ); document.write( "\n" ); document.write( "I have tried every formula that I can think of to get this one to work out correctly for me and I'm coming up short.\r
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\n" ); document.write( "\n" ); document.write( "Please help.\r
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Algebra.Com's Answer #125467 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
A parabolic satellite television antenna has a diameter of 6 feet and is 1.6 feet deep. How far is the focus from the vertex?
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\n" ); document.write( "Draw the parabola on an xy coordinate grill.
\n" ); document.write( "Put the vertex at (0,1.6)
\n" ); document.write( "Then the parabola will meet the x-axis at (-3,0) and (3,0)
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\n" ); document.write( "So the equation of the parabola will be y = -x^2 + 1.6
\n" ); document.write( "or x^2 = -y - 1.6
\n" ); document.write( "or x^2 = -(y+1.6)
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\n" ); document.write( "This has the form x^2 = 4p(y-k), so 4p = -1 and p = -1/4
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\n" ); document.write( "The distance from the vertex to the focus is p so the
\n" ); document.write( "focus is at y = 1.6-(1/4) = 1.6-0.25 = 1.375
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\n" ); document.write( "Ans: the focus is (1/4) ft. from the vertex.
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.\r
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