document.write( "Question 170004: A parabolic satellite television antenna has a diameter of 6 feet and is 1.6 feet deep. How far is the focus from the vertex?\r
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document.write( "I have tried every formula that I can think of to get this one to work out correctly for me and I'm coming up short.\r
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document.write( "Please help.\r
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document.write( "Thank you in advance \n" );
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Algebra.Com's Answer #125467 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! A parabolic satellite television antenna has a diameter of 6 feet and is 1.6 feet deep. How far is the focus from the vertex? \n" ); document.write( "---------------------------- \n" ); document.write( "Draw the parabola on an xy coordinate grill. \n" ); document.write( "Put the vertex at (0,1.6) \n" ); document.write( "Then the parabola will meet the x-axis at (-3,0) and (3,0) \n" ); document.write( "---------------- \n" ); document.write( "So the equation of the parabola will be y = -x^2 + 1.6 \n" ); document.write( "or x^2 = -y - 1.6 \n" ); document.write( "or x^2 = -(y+1.6) \n" ); document.write( "----------------- \n" ); document.write( "This has the form x^2 = 4p(y-k), so 4p = -1 and p = -1/4 \n" ); document.write( "--- \n" ); document.write( "The distance from the vertex to the focus is p so the \n" ); document.write( "focus is at y = 1.6-(1/4) = 1.6-0.25 = 1.375 \n" ); document.write( "------------------- \n" ); document.write( "Ans: the focus is (1/4) ft. from the vertex. \n" ); document.write( "====================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |