document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=169985>Question 169985</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 5.1.6. what are all of the trigonomic values given that cot=-3 and sin= square root 10/10 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #125453 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=125453\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> what are all of the trigonomic values given that cot=-3 and sin= square root 10/10<BR>\n" );
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document.write( "Keep in mind that x^2 + y^2 = r^2<BR>\n" );
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document.write( "cot=-3 = -3/1<BR>\n" );
document.write( "Since cot = x/y, x = -3 and y = 1<BR>\n" );
document.write( "Therefore r = sqrt(-3)^2 + 1^2) = sqrt(10)\r<BR>\n" );
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document.write( "Then:<BR>\n" );
document.write( "sin = y/r = 1/sqrt(10) = sqrt(10)/10<BR>\n" );
document.write( "cos = x/r = -3/sqrt(10)<BR>\n" );
document.write( "tan = y/x = -1/3<BR>\n" );
document.write( "csc = r/y = sqrt(10)<BR>\n" );
document.write( "sec = r/x = -sqrt(10)/3<BR>\n" );
document.write( "cot = -3<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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