document.write( "Question 169986: Can you please help show me how to solve this quadratic equation by completing the square\r
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Algebra.Com's Answer #125446 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
\"w%5E2-5w=14\" Start with the given equation.\r
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\n" ); document.write( "\n" ); document.write( "Take half of the \"w\" coefficient -5 to get \"-5%2F2\". Now square \"-5%2F2\" to get \"%28-5%2F2%29%5E2=25%2F4\". Add this value to both sides\r
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\n" ); document.write( "\n" ); document.write( "\"w%5E2-5w%2B25%2F4=14%2B25%2F4\" Add \"25%2F4\" to both sides\r
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\n" ); document.write( "\n" ); document.write( "\"w%5E2-5w%2B25%2F4=81%2F4\" Combine like terms.\r
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\n" ); document.write( "\n" ); document.write( "\"4w%5E2-4%285w%29%2Bcross%284%29%2825%2Fcross%284%29%29=cross%284%29%2881%2Fcross%284%29%29\" Multiply EVERY term by the LCD 4 to clear the fractions\r
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\n" ); document.write( "\n" ); document.write( "\"4w%5E2-20w%2B25=81\" Multiply and simplify\r
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\n" ); document.write( "\n" ); document.write( "\"%282w-5%29%5E2=81\" Factor \"4w%5E2-20w%2B25\" to get \"%282w-5%29%5E2\"\r
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\n" ); document.write( "\n" ); document.write( "\"2w-5=0%2B-sqrt%2881%29\" Take the square root of both sides\r
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\n" ); document.write( "\n" ); document.write( "\"2w-5=9\" or \"2w-5=-9\" Break up the \"plus/minus\" to form two equations\r
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\n" ); document.write( "\n" ); document.write( "\"2w-5=sqrt%2881%29\" or \"2w-5=-sqrt%2881%29\" Take the square root of 81 to get 9\r
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\n" ); document.write( "\n" ); document.write( "\"2w=5%2B9\" or \"2w=5-9\" Add 5 to both sides\r
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\n" ); document.write( "\n" ); document.write( "\"2w=14\" or \"2w=-4\" Combine like terms.\r
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\n" ); document.write( "\n" ); document.write( "\"w=14%2F2\" or \"w=-4%2F2\" Divide both sides by 2 to isolate \"w\"\r
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\n" ); document.write( "\n" ); document.write( "\"w=7\" or \"w=-2\" Divide\r
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\n" ); document.write( "\n" ); document.write( "So the answers are \"w+=+7\" or \"w+=+-2\" \r
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