document.write( "Question 169983: Can you please show me how to work this equation out using the quadratic formula.\r
\n" ); document.write( "\n" ); document.write( "w^2 - 5w + 5 = 0\r
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Algebra.Com's Answer #125445 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "\"w%5E2-5w%2B5=0\" Start with the given equation.\r
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\n" ); document.write( "\n" ); document.write( "Notice we have a quadratic equation in the form of \"aw%5E2%2Bbw%2Bc\" where \"a=1\", \"b=-5\", and \"c=5\"\r
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\n" ); document.write( "\n" ); document.write( "Let's use the quadratic formula to solve for w\r
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\n" ); document.write( "\n" ); document.write( "\"w+=+%28-b+%2B-+sqrt%28+b%5E2-4ac+%29%29%2F%282a%29\" Start with the quadratic formula\r
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\n" ); document.write( "\n" ); document.write( "\"w+=+%28-%28-5%29+%2B-+sqrt%28+%28-5%29%5E2-4%281%29%285%29+%29%29%2F%282%281%29%29\" Plug in \"a=1\", \"b=-5\", and \"c=5\"\r
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\n" ); document.write( "\n" ); document.write( "\"w+=+%285+%2B-+sqrt%28+%28-5%29%5E2-4%281%29%285%29+%29%29%2F%282%281%29%29\" Negate \"-5\" to get \"5\". \r
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\n" ); document.write( "\n" ); document.write( "\"w+=+%285+%2B-+sqrt%28+25-4%281%29%285%29+%29%29%2F%282%281%29%29\" Square \"-5\" to get \"25\". \r
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\n" ); document.write( "\n" ); document.write( "\"w+=+%285+%2B-+sqrt%28+25-20+%29%29%2F%282%281%29%29\" Multiply \"4%281%29%285%29\" to get \"20\"\r
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\n" ); document.write( "\n" ); document.write( "\"w+=+%285+%2B-+sqrt%28+5+%29%29%2F%282%281%29%29\" Subtract \"20\" from \"25\" to get \"5\"\r
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\n" ); document.write( "\n" ); document.write( "\"w+=+%285+%2B-+sqrt%28+5+%29%29%2F%282%29\" Multiply \"2\" and \"1\" to get \"2\". \r
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\n" ); document.write( "\n" ); document.write( "\"w+=+%285%2Bsqrt%285%29%29%2F%282%29\" or \"w+=+%285-sqrt%285%29%29%2F%282%29\" Break up the expression. \r
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\n" ); document.write( "\n" ); document.write( "So the answers are \"w+=+%285%2Bsqrt%285%29%29%2F%282%29\" or \"w+=+%285-sqrt%285%29%29%2F%282%29\" \r
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\n" ); document.write( "\n" ); document.write( "which approximate to \"w=3.618\" or \"w=1.382\"
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