document.write( "Question 169953This question is from textbook
\n" ); document.write( ": 825jane hooker invested $ 40,000 in 3 parts. One part in Mutual fund 2% per year.Second part, amount twice the first, govenment bonds 2.5% per year.the rest in savings account that pays 1.25% annual interest. during the first year, total investment is $ 825. how much did she invest at each rate. \n" ); document.write( "
Algebra.Com's Answer #125413 by checkley77(12844)\"\" \"About 
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.02x+.025*2x+.0125(40,000-3x)=825
\n" ); document.write( ".02x+.05x+500-.0375x=825
\n" ); document.write( ".0325x=825-500
\n" ); document.write( ".0325x=325
\n" ); document.write( "x=325/.0325
\n" ); document.write( "x=10,000 invested @ 2%
\n" ); document.write( "10,000*2=20,000 invested @
\n" ); document.write( "40,000-10,000-20,000=10,000 invested @ 1.25%
\n" ); document.write( "Proof:
\n" ); document.write( ".02*10,000+.025*20,000+.0125*10,000=825
\n" ); document.write( "200+500+125=825
\n" ); document.write( "825=825
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