document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=169220>Question 169220</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help<BR>\n" );
document.write( "Find the sum of the infinite geometric series 36+24+16+...if it exists.<BR>\n" );
document.write( "I must show my work and am lost.<BR>\n" );
document.write( "Thanks </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #125402 by </B><A HREF=/tutors/aboutme.mpl?userid=chiefman><B>chiefman(11)</B></A><img src=\"/images/stars/stars-06.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=chiefman><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=chiefman><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=125402\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 36+24+16+....... <BR>\n" );
document.write( "we have the first term (a)=36<BR>\n" );
document.write( "now finding common ratio(r) we have<BR>\n" );
document.write( "r=24/36 or 16/24 which gives 2/3<BR>\n" );
document.write( "using the formula <BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=S=%28a%2F%281-r%29%29 ALIGN=MIDDLE  ALT=\"S=%28a%2F%281-r%29%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > where a=first term,r=common ratio and S is the sum to infinity<BR>\n" );
document.write( "we have S=36/(1-2/3)<BR>\n" );
document.write( " =108 Ans </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );