document.write( "Question 169936: 3x^2-2x+1=0
\n" ); document.write( "solve the equation and present in solution set notation
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Algebra.Com's Answer #125370 by nerdybill(7384)\"\" \"About 
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3x^2-2x+1=0
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\n" ); document.write( "Factoring the left side:
\n" ); document.write( "(3x+1)(x-1) = 0
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\n" ); document.write( "Setting each term on the left to zero to find the set:
\n" ); document.write( "3x+1 = 0
\n" ); document.write( "3x = -1
\n" ); document.write( "x = -1/3
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\n" ); document.write( "x-1 = 0
\n" ); document.write( "x = 1
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\n" ); document.write( "Solution set:
\n" ); document.write( "x = {-1/3, 1}
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