document.write( "Question 169929: Solve the quadratic equation by completing the square:
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Algebra.Com's Answer #125361 by jim_thompson5910(35256)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "\"3x%5E2%2B6x-4\" Start with the right side of the equation.\r
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\n" ); document.write( "\n" ); document.write( "\"3%28x%5E2%2B2x-4%2F3%29\" Factor out the \"x%5E2\" coefficient \"3\". This step is very important: the \"x%5E2\" coefficient must be equal to 1.\r
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\n" ); document.write( "\n" ); document.write( "Take half of the \"x\" coefficient \"2\" to get \"1\". In other words, \"%281%2F2%29%282%29=1\".\r
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\n" ); document.write( "\n" ); document.write( "Now square \"1\" to get \"1\". In other words, \"%281%29%5E2=%281%29%281%29=1\"\r
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\n" ); document.write( "\n" ); document.write( "\"3%28x%5E2%2B2x%2Bhighlight%281-1%29-4%2F3%29\" Now add and subtract \"1\" inside the parenthesis. Make sure to place this after the \"x\" term. Notice how \"1-1=0\". So the expression is not changed.\r
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\n" ); document.write( "\n" ); document.write( "\"3%28%28x%5E2%2B2x%2B1%29-1-4%2F3%29\" Group the first three terms.\r
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\n" ); document.write( "\n" ); document.write( "\"3%28%28x%2B1%29%5E2-1-4%2F3%29\" Factor \"x%5E2%2B2x%2B1\" to get \"%28x%2B1%29%5E2\".\r
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\n" ); document.write( "\n" ); document.write( "\"3%28%28x%2B1%29%5E2-7%2F3%29\" Combine like terms.\r
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\n" ); document.write( "\n" ); document.write( "\"3%28x%2B1%29%5E2%2B3%28-7%2F3%29\" Distribute.\r
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\n" ); document.write( "\n" ); document.write( "\"3%28x%2B1%29%5E2-7\" Multiply.\r
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\n" ); document.write( "\n" ); document.write( "So after completing the square, \"3x%5E2%2B6x-4\" transforms to \"3%28x%2B1%29%5E2-7\". So \"3x%5E2%2B6x-4=3%28x%2B1%29%5E2-7\".\r
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\n" ); document.write( "\n" ); document.write( "So \"3x%5E2%2B6x-4=0\" is equivalent to \"3%28x%2B1%29%5E2-7=0\".\r
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\n" ); document.write( "\n" ); document.write( "\"3%28x%2B1%29%5E2-7=0\" Start with the given equation.\r
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\n" ); document.write( "\n" ); document.write( "\"3%28x%2B1%29%5E2=0%2B7\"Add \"7\" to both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"3%28x%2B1%29%5E2=7\" Combine like terms.\r
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\n" ); document.write( "\n" ); document.write( "\"%28x%2B1%29%5E2=%287%29%2F%283%29\" Divide both sides by \"3\".\r
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\n" ); document.write( "\n" ); document.write( "\"x%2B1=0%2B-sqrt%287%2F3%29\" Take the square root of both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"x%2B1=sqrt%287%2F3%29\" or \"x%2B1=-sqrt%287%2F3%29\" Break up the \"plus/minus\" to form two equations.\r
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\n" ); document.write( "\n" ); document.write( "\"x%2B1=sqrt%2821%29%2F3\" or \"x%2B1=-sqrt%2821%29%2F3\" Simplify the square root.\r
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\n" ); document.write( "\n" ); document.write( "\"x=-1%2Bsqrt%2821%29%2F3\" or \"x=-1-sqrt%2821%29%2F3\" Subtract \"1\" from both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"x=%28-3%2Bsqrt%2821%29%29%2F%283%29\" or \"x=%28-3-sqrt%2821%29%29%2F%283%29\" Combine the fractions.\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So the solutions are \"x=%28-3%2Bsqrt%2821%29%29%2F%283%29\" or \"x=%28-3-sqrt%2821%29%29%2F%283%29\".\r
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