document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=169879>Question 169879</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Mary Grace invested a certain sum in an account that pays 6% interest and invested P10 000 more in another account that pays 10% interest. If the income from both investments was P34 000, then how much did he invest at each rate?\r<BR>\n" );
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document.write( "please give me your table for the solution </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #125343 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=125343\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Mary Grace invested a certain sum in an account that pays 6% interest and invested P10 000 more in another account that pays 10% interest. If the income from both investments was P34 000, then how much did he invest at each rate? <BR>\n" );
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document.write( "Interest Equation: 0.06x + 0.10*(x+10,000) = 34000<BR>\n" );
document.write( "6x + x + 10000 = 3400000<BR>\n" );
document.write( "5x = 3390000<BR>\n" );
document.write( "x = 678000 (amt. invested at 6%)<BR>\n" );
document.write( "x + 100000 = 688000 (amt. invested at 10%\r<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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