document.write( "Question 169519: What is the pressure, in mm Hg, of 39.0 g of CO2 gas at 31°C, contained in a 350 mL vessel? (VII-1)
\n" ); document.write( "_____mm Hg \n" ); document.write( "

Algebra.Com's Answer #125326 by jojo14344(1513) $\"\"$ $\"About$

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\n" ); document.write( "It follows Ideal Gas Law --------> $\"PV=nRT\"$ , Working Eqn
\n" ); document.write( "where --->

\n" ); document.write( "Solving for $\"n\"$ :
\n" ); document.write( " $\"n=m%2Fhighlight%28MW%29\"$
\n" ); document.write( "where, $\"MW=%28NumberofAtoms%29%28AtomicWeight%29\"$
\n" ); document.write( "In $\"CO%5B2%5D\"$ , there are \"2\" atoms of Oxygen and \"1\" atom of Carbon.
\n" ); document.write( "Look on Periodic Table, we see $\"Oxygen\"$ has Atomic Weight ---> $\"16\"$ . Therefore, its Molecular Weight is expressed as $\"MW%5BO%5D=2%2A16=32\"$
\n" ); document.write( ".
\n" ); document.write( "For Carbon, look on Periodic Table and the Atomic Weight is ----> $\"12\"$ .
\n" ); document.write( "It's Molecular Weight is expressed as $\"MW%5BC%5D=1%2A12=12\"$
\n" ); document.write( ".
\n" ); document.write( "Therefore, $\"MW=MW%5BO%5D%2BMW%5BC%5D=32%2B12=44\"$
\n" ); document.write( "Subst.: $\"n=mass%2FMW=39cross%28g%29%2F%2844cross%28g%29%2Fmol%29\"$
\n" ); document.write( " $\"n=0.886mol\"$
\n" ); document.write( ".
\n" ); document.write( "Going Back our Working Eqn,
\n" ); document.write( " $\"P%280.350%29=%280.886%29%280.0821%29%28304.15%29\"$
\n" ); document.write( " $\"P%2Across%280.350%29%2Fcross%280.350%29=cross%2822.124%2963.211581%2Fcross%280.350%29\"$
\n" ); document.write( " $\"P=63.212atm\"$ ----------> mmHg?
\n" ); document.write( " $\"63.212cross%28atm%29%281mmHg%2F.001315789cross%28atm%29%29\"$
\n" ); document.write( " $\"highlight%2848044mmHg=Pressure%29\"$ , Answer
\n" ); document.write( ".
\n" ); document.write( "Thank you,
\n" ); document.write( "Jojo \n" ); document.write( "

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