document.write( "Question 169878: A total of P600 000 is deposited into two simple interest accounts. On one account the annual simple interest rate is 8%, while on the second account the annual simple interest rate is 12%. How much should be invested in each account so that the total annual interest earned is P52 000?\r
\n" ); document.write( "\n" ); document.write( "please give me the table of your solution.
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Algebra.Com's Answer #125297 by jojo14344(1513)\"\" \"About 
You can put this solution on YOUR website!
Let \"x\"= amount inv. @ 12%
\n" ); document.write( "So, \"600000-x\"=amount inv. @ 8%
\n" ); document.write( "It follows:
\n" ); document.write( "\"0.12x%2B0.08%28600000-x%29=52000\", EQN 1
\n" ); document.write( "\"0.12x%2B48000-0.08x=52000\"
\n" ); document.write( "\"0.04x=52000-48000=4000\"
\n" ); document.write( "\"cross%280.04%29x%2Fcross%280.04%29=cross%284000%29100000%2Fcross%280.04%29\"
\n" ); document.write( "x=100,000 ---------> amount inv. @ 12%
\n" ); document.write( ".
\n" ); document.write( "\"600000-100000\"=500,000 -------> amount inv.@8%
\n" ); document.write( "Let's check using Simple Annual Interest:
\n" ); document.write( "\"I=Prt\"
\n" ); document.write( "\"I%5B8%5D=500000%2A.08%2A1\"=40,000
\n" ); document.write( "\"I%5B12%5D=100000%2A.12%2A1\"=12,000
\n" ); document.write( "Therefore,\"I%5B8%5D%2BI%5B12%5D=I\"
\n" ); document.write( "\"40000%2B12000=52000\"
\n" ); document.write( "\"52000=52000\"
\n" ); document.write( "Thank you,
\n" ); document.write( "Jojo
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