document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=169876>Question 169876</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I looked at all the answers and still cannot figure it out. The question is:\r<BR>\n" );
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document.write( "Given the function  f(x) = x^2 + 3x + 4  , find the value of  f(–1). So, I think I am lost. I did it like this: <BR>\n" );
document.write( "fx=x^2+3x+3<BR>\n" );
document.write( "fx-2^2-3x-3=0<BR>\n" );
document.write( "x=0\r<BR>\n" );
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document.write( "However, that is not the answer. The answer is supposed to be f(–1) = 2. \r<BR>\n" );
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document.write( "I would appreciate it if you would show me how to resolve this. Thank you.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #125295 by </B><A HREF=/tutors/aboutme.mpl?userid=gonzo><B>gonzo(654)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=gonzo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=125295\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> if f(x) = x^2 + 3x + 3, then.....<BR>\n" );
document.write( "f(-1) = (-1)^2 + 3*(-1) + 4<BR>\n" );
document.write( "= 1 -3 + 4<BR>\n" );
document.write( "= -2 + 4<BR>\n" );
document.write( "= 2<BR>\n" );
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document.write( "you just replace x with (-1) and solve.<BR>\n" );
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