document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=169502>Question 169502</A>: <I><SPAN STYLE=\"word-break: break-all;\"> condense the expression log 3+ 1/2 log x-log 5 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #125292 by </B><A HREF=/tutors/aboutme.mpl?userid=chiefman><B>chiefman(11)</B></A><img src=\"/images/stars/stars-06.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=chiefman><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=chiefman><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=125292\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> log3+1/2logx-log5 this becomes<BR>\n" );
document.write( "log3+logx^1/2-log5 since( alogb=logb^a)<BR>\n" );
document.write( "log{(3*x^1/2)/5}since[loga+logb=logab],and [loga-logb=log(a/b)]<BR>\n" );
document.write( "hence the answer is <BR>\n" );
document.write( "log{(3*x^1/2)/5} </SPAN>\n" );
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