document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=169480>Question 169480</A>: <I><SPAN STYLE=\"word-break: break-all;\"> We are working on quadratic equations and I have no idea how to solve this.  Here is the question:  A rectangle has a perimiter of 52 feet and an area of 153 square feet.  Find the dimensions fo the rectangle.  I have tried to plug in the 2w+2L = 52. I factored out the 2 and divided it on both sides to get w=24-L.  I tried to plug this in also.  No luck.  Please help me with a formula to solve.\r<BR>\n" );
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document.write( "Thanks <BR>\n" );
document.write( "Shonnie </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #125291 by </B><A HREF=/tutors/aboutme.mpl?userid=chiefman><B>chiefman(11)</B></A><img src=\"/images/stars/stars-06.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=chiefman><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=chiefman><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=125291\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> given perimeter P=52<BR>\n" );
document.write( "area(A)=153\r<BR>\n" );
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document.write( "taking the perimeter of rectangle,<BR>\n" );
document.write( "P=2(l+w)and assigning length(l) to be x we have;<BR>\n" );
document.write( "p=2(x+w)since p=52 we have<BR>\n" );
document.write( "52=2(x+w)<BR>\n" );
document.write( "26=(x+w)therefore the width(w)becomes<BR>\n" );
document.write( "w=26-x<BR>\n" );
document.write( "since area=lw but l=x and w=26-x we have<BR>\n" );
document.write( "area(A)=x(26-x)<BR>\n" );
document.write( "153=x(26-x)<BR>\n" );
document.write( "153=26x-x^2 this reduces to aquadratic eqn<BR>\n" );
document.write( "x^2-26+153=0<BR>\n" );
document.write( "applying the quadratic formula <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x=%28-b%2B-sqrt%28b%5E2-4%2Aa%2Ac%29%29%2F%282%2Aa%29 ALIGN=MIDDLE  ALT=\"x=%28-b%2B-sqrt%28b%5E2-4%2Aa%2Ac%29%29%2F%282%2Aa%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >we have<BR>\n" );
document.write( "{x=(26+-sqrt(26^2-4*1*153))/(2*1)}the answer becomes<BR>\n" );
document.write( "x=17or 9ft<BR>\n" );
document.write( "L=17,W=26-17hence<BR>\n" );
document.write( "L=17,W=9<BR>\n" );
document.write( "check;A=lw<BR>\n" );
document.write( "17*9=153 </SPAN>\n" );
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