document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=169511>Question 169511</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A sample of helium gas has a volume of 4.00 L at a pressure of 0.180atm. What is its pressure if the volume is changed to 9.30 L while the temperature is held constant?<BR>\n" );
document.write( "_____atm </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #125288 by </B><A HREF=/tutors/aboutme.mpl?userid=chiefman><B>chiefman(11)</B></A><img src=\"/images/stars/stars-06.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=chiefman><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=chiefman><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=125288\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> recalling the standard formula p*v=k<BR>\n" );
document.write( "where p=pressure,v=volume and k=constant<BR>\n" );
document.write( "we have p1*v1=p2*v2 since temparature is contant we have<BR>\n" );
document.write( "p1=0.180atm<BR>\n" );
document.write( "v1=4.00L <BR>\n" );
document.write( "p2=?<BR>\n" );
document.write( "v2=9.30L<BR>\n" );
document.write( "making p2 to be the subject of our formula we have<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=p2=%28p1%2Av1%29%2F%28v2%29 ALIGN=MIDDLE  ALT=\"p2=%28p1%2Av1%29%2F%28v2%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "p2=(0.180*4.00)/9.30<BR>\n" );
document.write( "p2=0.077<BR>\n" );
document.write( "hence the new pressure=0.077atm </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );