document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=169546>Question 169546</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve the equation.\r<BR>\n" );
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document.write( "[1/8]^-2p=2^3p+2\r<BR>\n" );
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document.write( "a. p=2/3<BR>\n" );
document.write( "b. p=-2/9<BR>\n" );
document.write( "c. p=-9/2<BR>\n" );
document.write( "d. p=3/2 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #125287 by </B><A HREF=/tutors/aboutme.mpl?userid=chiefman><B>chiefman(11)</B></A><img src=\"/images/stars/stars-06.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=chiefman><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=chiefman><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=125287\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (1/8)^-2p=2^3p+2<BR>\n" );
document.write( "1/8 becomes 2^(-3) since 1/a=a^(-1)<BR>\n" );
document.write( "hence the eqn becomes 2^(-3)*-2p=2^3p+2<BR>\n" );
document.write( "cancelling the bases ie 2 we have<BR>\n" );
document.write( "(-3)*-2p=3p+2<BR>\n" );
document.write( "6p=3p+2<BR>\n" );
document.write( "taking like terms we have<BR>\n" );
document.write( "6p-3p=2<BR>\n" );
document.write( "3p=2<BR>\n" );
document.write( "p=2/3 </SPAN>\n" );
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