document.write( "Question 169868: HARRY IS FIVE YEARS OLDER THAN DON. THREE YEARS AGO DON WAS TWO-THIRDS AS OLD AS HARRY. HOW OLD IS HARRY? \r
\n" ); document.write( "\n" ); document.write( "I AM NOT SURE BUT I THINK ITS THE 2/3 THATS IS THROWING ME OFF.\r
\n" ); document.write( "\n" ); document.write( "THANKS :) \n" ); document.write( "
Algebra.Com's Answer #125284 by nerdybill(7384)\"\" \"About 
You can put this solution on YOUR website!
HARRY IS FIVE YEARS OLDER THAN DON. THREE YEARS AGO DON WAS TWO-THIRDS AS OLD AS HARRY. HOW OLD IS HARRY?
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\n" ); document.write( "Let x = Don's age
\n" ); document.write( "then from \"HARRY IS FIVE YEARS OLDER THAN DON.\" we have:
\n" ); document.write( "x+5 = Harry's age
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\n" ); document.write( "Finally, from \"THREE YEARS AGO DON WAS TWO-THIRDS AS OLD AS HARRY.\" we get our equation: (three years ago means current year minus 3)
\n" ); document.write( "x-3 = (2/3)(x+5-3)
\n" ); document.write( "x-3 = (2/3)(x+2)
\n" ); document.write( "3x-9 = 2(x+2)
\n" ); document.write( "3x-9 = 2x+4
\n" ); document.write( "x-9 = 4
\n" ); document.write( "x = 13 years (Don's age)
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\n" ); document.write( "Harry's age:
\n" ); document.write( "x+5 = 13+5 = 18 years\r
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