document.write( "Question 169776: The top and bottom margins of a poster are each 6 cm and the side margins are each 4cm. If the area of printed material on the poster is fixed at 384cm^3, find the dimensions of the poster with the smallest area?\r
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Algebra.Com's Answer #125273 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! The top and bottom margins of a poster are each 6 cm and the side margins are each 4cm. If the area of printed material on the poster is fixed at 384cm^2, find the dimensions of the poster with the smallest area? \n" ); document.write( "--------------------------- \n" ); document.write( "Assume the printed area is a square. \n" ); document.write( "It's dimensions are each sqrt(384) \n" ); document.write( "------------------------------------- \n" ); document.write( "If you include the margins the dimensions are as follows: \n" ); document.write( "length = sqrt(384)+12cm \n" ); document.write( "width = sqrt(384) + 8cm \n" ); document.write( "------------- \n" ); document.write( "The total area of the poster is LW = 384 + 96 + 20sqrt(384) \n" ); document.write( "= 480 + 20sqrt(384) \n" ); document.write( "----------------- \n" ); document.write( "The area of the margin is total area - printed material area \n" ); document.write( "= 480 + 20sqrt(384) - 384 = 96+20sqrt(384) = 387.92 cm^2 \n" ); document.write( "================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " \n" ); document.write( " |