document.write( "Question 169542: The perimeter of a rectangle window is 32 ft. Find the dimensions of the window that will enclose the largest area. \n" ); document.write( "
Algebra.Com's Answer #125252 by nerdybill(7384)![]() ![]() You can put this solution on YOUR website! The perimeter of a rectangle window is 32 ft. Find the dimensions of the window that will enclose the largest area. \n" ); document.write( ". \n" ); document.write( "Let W = width \n" ); document.write( "and L = length \n" ); document.write( ". \n" ); document.write( "Since perimeter is: \n" ); document.write( "2(L + W) = 32 \n" ); document.write( "L + W = 16 \n" ); document.write( "L = 16-W \n" ); document.write( ". \n" ); document.write( "Area = W(16-W) \n" ); document.write( "Area = -W^2 + 16W \n" ); document.write( ". \n" ); document.write( "By inspection, we see (from the -1 coefficient associated with W^2) that it is a parabola which opens downward -- therefore, the \"axis of symmetry\" should give you the max. \n" ); document.write( ". \n" ); document.write( "Axis of symmetry: \n" ); document.write( "W = -b/2a \n" ); document.write( "W = -16/2(-1) \n" ); document.write( "W = 8 feet (width) \n" ); document.write( ". \n" ); document.write( "Length: \n" ); document.write( "16-W = 16-8 = 8 feet (length)\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |